5j^3-80j=0

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Solution for 5j^3-80j=0 equation:


Simplifying
5j3 + -80j = 0

Reorder the terms:
-80j + 5j3 = 0

Solving
-80j + 5j3 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '5j'.
5j(-16 + j2) = 0

Factor a difference between two squares.
5j((4 + j)(-4 + j)) = 0

Ignore the factor 5.

Subproblem 1

Set the factor 'j' equal to zero and attempt to solve: Simplifying j = 0 Solving j = 0 Move all terms containing j to the left, all other terms to the right. Simplifying j = 0

Subproblem 2

Set the factor '(4 + j)' equal to zero and attempt to solve: Simplifying 4 + j = 0 Solving 4 + j = 0 Move all terms containing j to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + j = 0 + -4 Combine like terms: 4 + -4 = 0 0 + j = 0 + -4 j = 0 + -4 Combine like terms: 0 + -4 = -4 j = -4 Simplifying j = -4

Subproblem 3

Set the factor '(-4 + j)' equal to zero and attempt to solve: Simplifying -4 + j = 0 Solving -4 + j = 0 Move all terms containing j to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + j = 0 + 4 Combine like terms: -4 + 4 = 0 0 + j = 0 + 4 j = 0 + 4 Combine like terms: 0 + 4 = 4 j = 4 Simplifying j = 4

Solution

j = {0, -4, 4}

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